Focal chord length of parabola
WebThe length of a focal chord of the parabola y 2=4ax at a distance b from the vertex is c. Then. A a 2=bc B a 3=b 2c C b 2=ac D b 2c=4a 3 Medium Solution Verified by Toppr Correct option is D) Parabola P:y²=4ax−−(1) Vertex =O(0,0) Focus: F(a,0) Let the Focal chord L be (y−0)=m(x−a) So y=mx−ma−−(2)\ Given b = Distance of O from L. WebApr 6, 2024 · Length of focal chord c = 4 a 3 P 2. Hence, we got the required length as 4 a 3 P 2. Note: The length of a focal chord of a parabola varies inversely as the square of the distance from its vertex. If …
Focal chord length of parabola
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WebThe extremities of a focal chord of the parabola y 2 = 4ax may be taken as the points t and –1/t. Length of the chord The abscissae of the points common to the straight line y = mx + c and the parabola y 2 = 4ax are given by the equation m 2 x 2 + (2mx – 4a) x + c 2 = 0. Length of the chord. As in the preceding article, the abscissae of the points … Buy Parabola Study Material (Mathematics) online for JEE Main/Advanced at … WebThe minimum length for any focal chord is evidently obtained when t =±1, t = ± 1, which gives us the LR. Thus, the smallest focal chord in any parabola is its LR. Example – 8. Prove that the circle described on any focal chord …
WebLength of the focal chords of the parabola y 2=4ax at a distance p from the vertex is A p2a 2 B p 2a 2 C p 24a 3 D ap 2 Hard Solution Verified by Toppr Correct option is C) y 2=4ax Slope of OP= Slope of OQ ⇒t 2= t 1−1 ∴ P(at 2,2at) & Q(t 2a, t−2a) Let length of focal chord be C. ∴ (at 2− t 2a)2+(2at+ t2a)2=C ⇒ a 2(t 2− t 21)2+(2a) 2(t+ t1)2=C WebApr 11, 2024 · The length of the focal chord which makes an angle θ with positive x-axis is 4a cosec 2 θ. Semi latus rectum is a harmonic mean between the segments of any focal …
WebLength of the focal chords of the parabola y 2=4ax at a distance p from the vertex is A p2a 2 B p 2a 2 C p 24a 3 D ap 2 Hard Solution Verified by Toppr Correct option is C) y 2=4ax … WebNov 20, 2013 · This is the length of the focal chord (the "width" of a parabola at focal level). Let x 2 = 4 p y be a parabola. Then F ( 0, p) is the focus. Consider the line that passes through the focus and parallel to the directrix. Let A and A ′ be the intersections of the line and the parabola. Then A ( − 2 p, p), A ′ ( 2 p, p), and A A ′ = 4 p. Share Cite
WebThe length of a focal chord of the parabola y2 =4ax at a distance ‘b’ from the vertex is ‘c’, then A 2a2=bc B a3=b2c C b2 =ac D b2c=4a3 Solution The correct option is D b2c =4a3 Let the angle made by focal chord with x – axis be θ ∴ sinθ= b a Length of focal chord, c =4acosec2θ ⇒ c= 4a(a b)2 ⇒ b2c =4a3 Suggest Corrections 28 Similar questions Q.
WebSolution The correct option is A (8, –8) For the parabola y2 = 8x; focus S (2, 0). Given point is P (1 2,2) Slope of ←→ SP is 2−0 1 2−2 = −4 3 Equation to ←→ SP is4x+3y−8= 0 4x+3y−8= 0⇒ 4x=8−3y Substituting this value of 4x in y2 = 8x we get y2 = 2(8−3y) ⇒y2+6y−16−16 =0 ⇒(y+8)(y−2) = 0 ⇒ y= 2or−8 y =−8 ⇒4x =8−3(−8)= 32⇒ x= 8 ∴ point … dhhs manual policy ncWebThe length of the focal chord of parabola \( y^{2}=4 a x \)P that makes an angle \( \alpha \) with the \( x \)-axis, is:W.(1) \( 4 a \sec ^{2} \alpha \)(2) \... cigna episodes of careWebAnswer: Consider the parabola: The distance between the vertex and the focus, measured along the axis of symmetry, is the "focal length". The "latus rectum" is the chord of the parabola which is parallel to the directrix and passes through the focus. In fact the “latus rectum” used to be calle... dhhs mandatory reportingWebSimplifying gives us the formula for a parabola: x 2 = 4py In more familiar form, with " y = " on the left, we can write this as: \displaystyle {y}=\frac { {x}^ {2}} { { {4} {p}}} y = 4px2 where p is the focal distance of the parabola. Now let's see what "the locus of points equidistant from a point to a line" means. cignaevernorthmychartWeb(v) Length of the focal chord having t 1 and t 2 as end points is a (t 1 — t 1) 2. (vi) Chord of contact drawn from a point (x 1, y 1) to the parabola y 2 = 4ax is yy 1, = 2a (x + x 1) (vii) Equation of the chord of the parabola y 2 = 4ax, which is bisected at (x 1 , y 1) is given by T = S 1 i.e. , yy 1 — 2a (x + x 1) = y 12 – 4ax dhhs massage therapy nebraskaWebPARABOLA ASSIGNMENT - Read online for free. Scribd is the world's largest social reading and publishing site. PARABOLA ASSIGNMENT. Uploaded by mynameis 1609. 0 ratings 0% found this document useful (0 votes) 0 views. 19 pages. Document Information click to expand document information. dhhs mandated reporter lineWebAssertion A: The least length of the focal chord of y 2 = 4 a x is 4 a. Reason R: Length of the focal chord of y 2 = 4 a x which makes an angle θ with its axis is 4 a cosec 2 θ. dhhs manuals michigan